Integrand size = 24, antiderivative size = 72 \[ \int \frac {x^2}{\left (-2+b x^2\right ) \left (-1+b x^2\right )^{3/4}} \, dx=\frac {\arctan \left (\frac {\sqrt {b} x}{\sqrt {2} \sqrt [4]{-1+b x^2}}\right )}{\sqrt {2} b^{3/2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} x}{\sqrt {2} \sqrt [4]{-1+b x^2}}\right )}{\sqrt {2} b^{3/2}} \]
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Time = 0.02 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.042, Rules used = {453} \[ \int \frac {x^2}{\left (-2+b x^2\right ) \left (-1+b x^2\right )^{3/4}} \, dx=\frac {\arctan \left (\frac {\sqrt {b} x}{\sqrt {2} \sqrt [4]{b x^2-1}}\right )}{\sqrt {2} b^{3/2}}-\frac {\text {arctanh}\left (\frac {\sqrt {b} x}{\sqrt {2} \sqrt [4]{b x^2-1}}\right )}{\sqrt {2} b^{3/2}} \]
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Rule 453
Rubi steps \begin{align*} \text {integral}& = \frac {\tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {2} \sqrt [4]{-1+b x^2}}\right )}{\sqrt {2} b^{3/2}}-\frac {\tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {2} \sqrt [4]{-1+b x^2}}\right )}{\sqrt {2} b^{3/2}} \\ \end{align*}
Time = 1.79 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.86 \[ \int \frac {x^2}{\left (-2+b x^2\right ) \left (-1+b x^2\right )^{3/4}} \, dx=\frac {\arctan \left (\frac {\sqrt {b} x}{\sqrt {2} \sqrt [4]{-1+b x^2}}\right )-\text {arctanh}\left (\frac {\sqrt {b} x}{\sqrt {2} \sqrt [4]{-1+b x^2}}\right )}{\sqrt {2} b^{3/2}} \]
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\[\int \frac {x^{2}}{\left (b \,x^{2}-2\right ) \left (b \,x^{2}-1\right )^{\frac {3}{4}}}d x\]
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Leaf count of result is larger than twice the leaf count of optimal. 144 vs. \(2 (55) = 110\).
Time = 0.29 (sec) , antiderivative size = 275, normalized size of antiderivative = 3.82 \[ \int \frac {x^2}{\left (-2+b x^2\right ) \left (-1+b x^2\right )^{3/4}} \, dx=\left [-\frac {2 \, \sqrt {2} \sqrt {b} \arctan \left (\frac {\sqrt {2} {\left (b x^{2} - 1\right )}^{\frac {1}{4}}}{\sqrt {b} x}\right ) - \sqrt {2} \sqrt {b} \log \left (-\frac {b^{2} x^{4} - 2 \, \sqrt {2} {\left (b x^{2} - 1\right )}^{\frac {1}{4}} b^{\frac {3}{2}} x^{3} + 4 \, \sqrt {b x^{2} - 1} b x^{2} + 4 \, b x^{2} - 4 \, \sqrt {2} {\left (b x^{2} - 1\right )}^{\frac {3}{4}} \sqrt {b} x - 4}{b^{2} x^{4} - 4 \, b x^{2} + 4}\right )}{4 \, b^{2}}, \frac {2 \, \sqrt {2} \sqrt {-b} \arctan \left (\frac {\sqrt {2} {\left (b x^{2} - 1\right )}^{\frac {1}{4}} \sqrt {-b}}{b x}\right ) - \sqrt {2} \sqrt {-b} \log \left (-\frac {b^{2} x^{4} - 2 \, \sqrt {2} {\left (b x^{2} - 1\right )}^{\frac {1}{4}} \sqrt {-b} b x^{3} - 4 \, \sqrt {b x^{2} - 1} b x^{2} + 4 \, b x^{2} + 4 \, \sqrt {2} {\left (b x^{2} - 1\right )}^{\frac {3}{4}} \sqrt {-b} x - 4}{b^{2} x^{4} - 4 \, b x^{2} + 4}\right )}{4 \, b^{2}}\right ] \]
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\[ \int \frac {x^2}{\left (-2+b x^2\right ) \left (-1+b x^2\right )^{3/4}} \, dx=\int \frac {x^{2}}{\left (b x^{2} - 2\right ) \left (b x^{2} - 1\right )^{\frac {3}{4}}}\, dx \]
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\[ \int \frac {x^2}{\left (-2+b x^2\right ) \left (-1+b x^2\right )^{3/4}} \, dx=\int { \frac {x^{2}}{{\left (b x^{2} - 1\right )}^{\frac {3}{4}} {\left (b x^{2} - 2\right )}} \,d x } \]
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\[ \int \frac {x^2}{\left (-2+b x^2\right ) \left (-1+b x^2\right )^{3/4}} \, dx=\int { \frac {x^{2}}{{\left (b x^{2} - 1\right )}^{\frac {3}{4}} {\left (b x^{2} - 2\right )}} \,d x } \]
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Timed out. \[ \int \frac {x^2}{\left (-2+b x^2\right ) \left (-1+b x^2\right )^{3/4}} \, dx=\int \frac {x^2}{{\left (b\,x^2-1\right )}^{3/4}\,\left (b\,x^2-2\right )} \,d x \]
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